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add x amount of days to fixed date


Jay Ess
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Question

i have a fixed date of 1/1/1900 and am duing a calculation which retruns me x amount of days, what is the easiest way to add the days to the fixed date to return me the date in question?

 

for example i am trying to add 44444 days to the 1/1/1900

 

would i do it like this?

local fixed = os.time({year=1900,month=1,day=1})

then convert the 44444 days to seconds by

local x  44444

local xInSecs = x * 1000*60 * 60 *24

local rTable= os.date("*t",fixed + xInsecs)

local resultInDate = rTable.Year....?

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1 hour ago, Jay Ess said:

i have a fixed date of 1/1/1900 and am duing a calculation which retruns me x amount of days, what is the easiest way to add the days to the fixed date to return me the date in question?

 

for example i am trying to add 44444 days to the 1/1/1900

 

would i do it like this?

local fixed = os.time({year=1900,month=1,day=1})

then convert the 44444 days to seconds by

local x  44444

local xInSecs = x * 1000*60 * 60 *24

local rTable= os.date("*t",fixed + xInsecs)

local resultInDate = rTable.Year....?

The thinking is right, going over os.time/date and epoch time will guarantee that you get leap years right.

Don't multiply with 1000 though...

The question is what date you want to get out at the end?

Either the table with os.date and "*t" or a string with os.date a "%c" format or  similar.

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