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LUA: Extract XML(GET) - REPLACE TAG VALUE - UPLOAD (PUT)


Question

Good Morning Guys,

I need to create a Virtual Device in order to enable/disable some functionality of my devices.

Shortly in need to extract the XML, modify a tag value, re-upload the xml.

 

I have understood that using "Net.FHttp"  and GET/PUT command im able to RETRIEVE and PUT the XML....

Example: response,status,errorcode = device:GET('URL')

Example: response,status,errorcode = device:PUT('URL',XML)

 

But how the entire process can be writed in LUA?

1) How to store in a variable the entire XML extracted using teh GET command?

2) How to replace the xml tag parameter ? ex. from enable to disable 

3) How to re-upload the modified XML?

 

Thanks in advnace

Regards

Gianluca

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  • 16 hours ago, 10der said:

    example

     

     

    Please login or register to see this code.

     

     

    Thanks a lot for your example.

    If i understand well this code retrieve the xml and check the status of your cam.

    We can use the "response" variable and replace a value into a tag in the xml retrieved and PUT again the entire code...

     

    Any idea?

     

    Edited by Gianluca S.
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