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lua code help


Martin555
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Question

Hi I have data in HEX format it is a long string of numbers and letters. It still start with 5C75303030 and ends
with numbers or letters. I would like to to save the last 6 values after value 5C75303030 in the table, or if is some
value after 5C75303030.
How I can do it?

String is for example:

5B22 AA557FC0 5C7530303031868C 5C7530303045F6 5C7530303030 5C7530303046 5C7530303031 5C75303030357B 5C7530303030 5C7530303132 5C7530303030 5C7530303031F1 5C7530303030 5C7530303033 5C753030303050 5C7530303030FD 5C75303030306D 5C753030303064

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  • So I will try it. But there is a problem. It's not that.  That string still starts with 5C303030 but has different lengths .

    that's the result:

    "31868","45B85","465C7","35405","305C7","305C7","30505","304E5","30645","30385","335C7","305C7","305C7","305C7","315C7","305C7"........................

     

    1 is ok, 2 is ok 3 is not Ok it has value 5c7 etc...

     

    After the assignment, I received these results, where in the result there is also 5C7... Wouldn't it be better to find 5C in a string and save 4 values to a table before value 5C? It sends the values after 5C75303030 and selects the values to the next 5C. wouldn't that be better? Is there a command for this?

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    Edited by Martin555
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    Eh, I don't think I understand. The code I posted solved your example in the first post. 

    Can you give a new example with input string and wanted output table?

     

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  • This is string code for eample:

    5B22AA557FC05C7530303031868C5C7530303045F65C75303030305C75303030465C75303030315C75303030357B5C75303030305C75303031325C75303030305C7530303031F15C75303030305C75303030335C7530303030505C7530303030FD5C75303030306D5C7530303030645C7530303030645C75303030305C225C75303030305C225F5C7530303033

     

    I need value underlined. so example  5C7530303031868C  I need 868C  for example 5C73030305C22  I need 5C22,    for example 5C7530303033 I need 33.  for example 5C7530303031EB I need EB

     

    It will probably be better to select each part 5C75303030XXX in the table at the beginning and then solve each position separately with the gsub command

     

    Edited by Martin555
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