Help with Sommer Garage Door duoVision 650 and SI

[zavjah 0]

Dear community,

 

I'd like to use SI to 

1. Open/Close my garage and

2. Indicate the status open/closed 

 

No1. 1 is not the issue:

• On the Garage door board there is constant 24V DV on PINs 9 (+) and 10 (GND) and this I use to power the SI
• OUT1 is then connected to PINs 5 and 6 which is a signal to open/stop/close/stop and so on the door

 

The to get the no. 2 solved I have a slightly different situation than described in the manual, because I do not have two signals on the garage door board, one for open and one for closed, but just one: PINs 11 (+) and 12 (GND) provide 34V DC when door is open and 0V when door is closed. This is achieved by interrupting the GND line, not the +. Hence, I cannot use the same GND like for power because 10 (GND) and 11 (+) always deliver 34V.

 

So my question is - provided I reduce the 34V to below 10V DC - if I connect PINs 11 and 12 like in this diagram, will this work:

 

Please login or register to see this attachment.

 

Thx for any help or suggestions,

zavjah

[Martin_N 154]

@zavjah

Hello.

Pins 11 and 12 are primarily used to connect the warning light. It also depends on the DIP switch settings. Be careful, this is an unstabilized 24V voltage (it can provide up to 36V when idle, which the SI cannot load so that this voltage drops).

I recommend connecting a relay to these terminals and galvanically isolating the SmartImplant input by connecting it to the contact of this relay.

36V at the input can damage the SI!

[zavjah 0]

Hello Martin, I am going to reduce the voltage to below 10V using resistors, that is not the issue. The thing is, if I assume, the voltage is always below 10V, will the connection like in the picture above, work? My doubts result of of two GND line being available with SI. If they are connected below the deck, then this would not work because I need a separate GND that only goes to IN1 and IN2.

[Martin_N 154]

@zavjah

I don't know why you're trying to reinvent the wheel?

And with all the problems associated with it?

I've already written about it. Put it on the coil of the isolating relay on terminals 11 and 12. Connect GND from SI and IN1 from SI to the contact of this relay.

Then you won't be bothered by the difference in ground potential, etc. The SI input in 0-10V mode has its own specifics and it is definitely necessary to have the same GND of the power supply and measured circuit.

USE RELAY!.

[zavjah 0]

Hello Martin, if it look slike I am trying this than it is just because I do not get it, sorry for that. Could you please explain in a bit greater details what I am to do or share the link, where you have described this? 

 

thx a lot

[Martin_N 154]

6 hours ago, zavjah said:

where you have described this? 

Put it on the coil of the isolating relay on terminals 11 and 12. Connect GND from SI and IN1 from SI to the contact of this relay.

Then you won't be bothered by the difference in ground potential, etc. The SI input in 0-10V mode has its own specifics and it is definitely necessary to have the same GND of the power supply and measured circuit.

USE RELAY!.

 

 

[Martin_N 154]

@zavjah

Please login or register to see this spoiler.

I am attaching a picture of the connection.
Use a DC relay. They are produced in different voltage ranges. Most relays switch at 0.75xUn to 1.5xUn (for example Un = 28V) and open at 0.4xUn (some even less). There are DC relays that are capable of switching in the range of 5-110VDC.
The relay coil must be DC voltage. (You can also use a combined DC/AC coil option).
It depends only on you what you get.

eM.

[zavjah 0]

Hallo Martin,

 

thx so much, this helps a lot.

 

Do you have something like this in mind: 

Please login or register to see this link.

. This one works with 36V DC (garage door delivers 36V). What i am not sure is at which voltage it closes/opens. There is a data sheet there but I cannot read something out of it, tbh

 

Thx

Edited February 15, 2025 by zavjah

[Martin_N 154]

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You can use, for example, a Finder relay.

Ideally 40.31.9.28. This relay will easily handle higher voltages "no-load" and lower under load.

Theoretically, you can use a 24VDC version of the relay. Type 40.31.9.24 may be suitable.
The voltage of outputs 11 and 12 (no-load 36V) should decrease when the relay is connected. Of course, this is done on a load by connecting a light bulb up to 1A, so it is necessary to test and measure.

 

eM.